RE: [xsl] Sorting a NodeSet Contained Within a Variable

Subject: RE: [xsl] Sorting a NodeSet Contained Within a Variable
From: Bryan Tulloch <b.tulloch@xxxxxxxxxxxxx>
Date: Wed, 11 Jul 2001 18:04:28 +0100

Thanks for your guidance, but this isn't working 100% for me.
I can sort the node-set if it is comprised purely of nodes from my xml
source tree, but not if it consists entirely of the results of a series of
calculations (using count()) done on nodes from the source tree. In other
words, I want to put those results into a nodeset and sort them.


-----Original Message-----
From: Oliver Becker [mailto:obecker@xxxxxxxxxxxxxxxxxxxxxxx]
Sent: Tuesday, July 10, 2001 12:14 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Sorting a NodeSet Contained Within a Variable

Hi Bryan,

> I have a variable that constitutes a nodeset; is it possible to sort a
> variable nodeset? 

Well, you can't sort a node-set because sets are unordered. ;-)
What you can do is to process the nodes of a set in a specific order.

> I ask because I have not been able to get this to work
> (although I can sort nodesets that are not variables).

This isn't different from any other expression that evaluates to a node-set.

Just do either

<xsl:apply-templates select="$set">
   <xsl:sort .... />


<xsl:for-each select="$set">
   <xsl:sort .... />

Hope that helps,

|  ob|do        Dipl.Inf. Oliver Becker                             |
|  --+--        E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx             |
|  op|qo        WWW: |

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