Re: [xsl] Sorting a NodeSet Contained Within a Variable

Subject: Re: [xsl] Sorting a NodeSet Contained Within a Variable
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 11 Jul 2001 18:22:01 +0100
> In other words, I want to put those results into a nodeset and sort them.

As must be stated in the FAQ you can not do this in XSLT 1.0 without use
of a node-set() extension function.

Any use of xsl:variable  with content (as opposed to select attribute)
does not construct a node st but a result tree fragment. You can not
query into the structure of a result tree fragment at all, all you can
do is convert it to a string, or copy it to the result.

Most systems have an extension function ext:node-set() that allows you
to convert the result tree fragment into a node set (containing a single
node, a root node correspnding to the root pf the tree constructed by


This message has been checked for all known viruses by Star Internet
delivered through the MessageLabs Virus Scanning Service. For further
information visit or alternatively call
Star Internet for details on the Virus Scanning Service.

 XSL-List info and archive:

Current Thread