[xsl] Position of a result tree fragment

Subject: [xsl] Position of a result tree fragment
From: Laurence O Garfield <lgarfiel@xxxxxxxxxxxxxxxxxxx>
Date: Wed, 18 Jul 2001 18:08:14 -0500 (CDT)
If I am passing a result tree fragment from one template to another using
a variable, is there any way to determine what the fragment's position
within its parent was originally?  According to the XSLT spec I can't use
/, //, or [] on result tree fragments, so I can't use [position()].  Is
there some other way, or do I have to pass the position of the node
through as a second variable as well?

--Larry Garfield

DePaul Linux Users Group Secretary

-- "If at first you don't succeed, skydiving isn't for you." :-)

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