RE: [xsl] Position of a result tree fragment

Subject: RE: [xsl] Position of a result tree fragment
From: "Chris Bayes" <Chris@xxxxxxxxxxx>
Date: Thu, 19 Jul 2001 00:55:49 +0100
Add it's original position to the rtf when you make it.

Ciao Chris

XML/XSL Portal

>-----Original Message-----
>From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Laurence O
>Sent: 19 July 2001 00:08
>To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>Subject: [xsl] Position of a result tree fragment
>If I am passing a result tree fragment from one template to another using
>a variable, is there any way to determine what the fragment's position
>within its parent was originally?  According to the XSLT spec I can't use
>/, //, or [] on result tree fragments, so I can't use [position()].  Is
>there some other way, or do I have to pass the position of the node
>through as a second variable as well?
>--Larry Garfield
>DePaul Linux Users Group Secretary
>-- "If at first you don't succeed, skydiving isn't for you." :-)
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