Subject: RE: [xsl] getting XSL to ignore a line From: Samina Islam <samnaz123@xxxxxxxxx> Date: Fri, 20 Jul 2001 07:35:57 -0700 (PDT) |
> You must have in your XSL something like this : > <xsl:output method="xml" ... > doctype-system="blahblahblah"/> > > Just remove the attribute doctype-system, so it > become : > <xsl:output method="xml" ... /> my xsl stylesheet does not have <xsl:output method="xml" ... doctype-system="blahblahblah"/> do i need it? my looks like this: <?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:rdf="http://www.w3.org/1999/..." xmlns:moreover="http://w.moreover.com/"> <xsl:template match="/*"> <rdf:RDF> <xsl:apply-templates select="article" /> </rdf:RDF> </xsl:template> and so on... i tried adding: <xsl:output method="xml"/> but it still does not work. sorry I'm new to XML/XSL so I 'm not too familiar with all this. Samina __________________________________________________ Do You Yahoo!? Get personalized email addresses from Yahoo! Mail http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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