Subject: Re: [xsl] conditional copying of nodes? From: Joerg Pietschmann <joerg.pietschmann@xxxxxx> Date: Wed, 22 Aug 2001 11:08:08 +0200 |
"Hewko, Doug" <Doug.Hewko@xxxxxxxxxxxxxxx> wrote > I've got the copy working but how I can incorporate this into my sort? I am > trying to copy the existing <member> tree to <newmember> for the sorting. I'm not sure why you want to copy the member data. Actually, i'm not sure why you want grouping. I guess you want to have a list of all distinct groups, and a list of the members within the groups. Try the following: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" encoding="ISO-8859-1"/> <xsl:strip-space elements="*"/> <xsl:key name="contacts-by-group" match="member" use="group" /> <xsl:template match="teammembers"> <html><head><title>Contacts by group</title></head> <body> <!-- iterate over distinct groups --> <xsl:for-each select="member/group[not(preceding::group=.)]"> <xsl:sort select="."/> <h1>Group <xsl:value-of select="."/></h1> <!-- process all members of the current group --> <xsl:apply-templates select="key('contacts-by-group',.)"> <xsl:sort select="name"/> </xsl:apply-templates> </xsl:for-each> </body> </html> </xsl:template> <xsl:template match="member"> <h2><xsl:value-of select="name"/></h2> <p>Email: <xsl:value-of select="e_mail"/></p> <p>Phone: <xsl:value-of select="phone"/></p> </xsl:template> </xsl:stylesheet> HTH J.Pietschmann XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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