Subject: [xsl] XSL Sorting Question - Meunchian Method From: "Magick, Brian" <Brian.Magick@xxxxxxxxxx> Date: Wed, 7 Nov 2001 15:15:30 -0600 |
I've been reading Jenni Tennisons's web site and looking at the grouping examples to help solve a problem. One example uses the following XML and XSL to output something similar to this: Customer 1 * Project 1 * Project 2 Customer 2 * Project 1 Based on this XSL: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:key name="rows" match="PROROW" use="name"/> <xsl:template match="PROJECTS"> <xsl:apply-templates select="PROROW[generate-id(.) = generate-id(key('rows', name)[1])]"/> </xsl:template> <xsl:template match="PROROW"> <b> <xsl:value-of select="name"/> </b> <ul> <xsl:for-each select="key('rows', name)/project_name"> <li> <a href="projects_results.xml?project={../id}"> <xsl:value-of select="." /> </a> </li> </xsl:for-each> </ul> </xsl:template> </xsl:stylesheet> and this XML: (which differs slightly from the XML on her web page) <?xml version="1.0" encoding="UTF-8"?> <PROJECTS> <PROROW> <id>1</id> <name>Customer 1</name> <project_name>Project 1</project_name> <project_name>Project 2</project_name> </PROROW> <PROROW> <id>2</id> <name>Customer 2</name> <project_name>Project 1</project_name> </PROROW> </PROJECTS> I would like to mix this up a bit and sort by project_name outputting a list of customers per project like this: Project 1 *Customer 1 *Customer 2 Project 2 *Customer 1 I think the change is very subtle and minor to get here but so far I've been unsuccessful. Any pointers? Brian XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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