Subject: Re: [xsl] How to handle xsi prefix in XSLT From: Janusz Dalecki <janusz.dalecki@xxxxxxxxx> Date: Mon, 03 Dec 2001 13:53:38 +1100 |
I was using visual tool called "TIBCO Software Inc." without much success. I have downloaded XML Spy and it works - so it was a tool problem. Thanks for your help and the time you spent answering my questions. Janusz "Thomas B. Passin" wrote: > Using your original xml sample, and this stylesheet, this version of the > transformation works fine using either msxml3 or Saxon. You are going to > have to tell us what system and processors you use, and how you are trying > to produce the transformation, and how you are trying to use it. For > example, if you expect the processor to find the stylesheet from the > processing instruction in the xml file, that may not be working for a number > of reasons. > > BTW, your method for producing a "Root" element works fine, but it is a > little easier to get the same result like this: > > <xsl:template match='/'> > <Root> > <xsl:apply-templates/> > </Root> > </xsl:template> > > Tom P > > [Janusz Dalecki] > > Please forgive my ignorance, I am new to XSLT, I have fixed my XSLT to the > one > below which inserts a root element (?Root?) and I am still getting the same > error ? am I doing something stupid? > > <?xml version = "1.0" encoding = "UTF-8"?> > <xsl:stylesheet xmlns:xsl = "http://www.w3.org/1999/XSL/Transform" xmlns:xsi > = > "http://www.w3.org/2000/10/XMLSchema-instance" version = "1.0"> > > <xsl:template match = "/"> > <xsl:element name = "Root"> > <xsl:apply-templates/> > </xsl:element> > </xsl:template> > > <xsl:template match = "Command"> > <xsl:element name = "Transaction"> > <xsl:apply-templates select = "@*"/> > </xsl:element> > </xsl:template> > > <xsl:template match = "Command[@xsi:type]"> > <xsl:element name = "hhhhhhh"> > </xsl:element> > </xsl:template> > > </xsl:stylesheet> > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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