Re: [xsl] arguments for xsl:call-template

["Thomas B. Passin" <tpassin@xxxxxxxxxxxx>]

[Charly]

> Does anyone of you has any idea  how to call a template and passing with a
> node as argument.
> I'm trying the following .
>
> <xsl:template name="histogram">
>    <xsl:param name="path" />
>    <xsl:for-each select="$path">
>       <xsl:value-of select="@value"/>
>    </xsl:for-each>
> </xsl:template>
>
> <xsl:call-template name="histogram">
>    <xsl:with-param name="path" select="'/report/histo/bar'" />
> </xsl:call-template>
>
Just change to one set of quotes in the select attribute and the select will
return a set of nodes, just what you asked for.  In other words, your
attribute value as you wrote it is a string (because of the extra set of
quotes), and you want it to be a node-set.

Tom P

> my XML looks like .
> <report>
>    <histo>
>       <bar value="20" />
>       <bar value="30" />
>       <bar value="40" />
>       <bar value="50" />
>    </histo>
>
> </report>



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