Subject: Re: [xsl] arguments for xsl:call-template From: Pep Coll <pcoll@xxxxxxxxxxxxxxxxxxxxx> Date: Fri, 07 Dec 2001 16:01:38 +0100 |
Hi everyone. I'm a beginner with XSL . Does anyone of you has any idea how to call a template and passing with a node as argument. I'm trying the following .
<xsl:template name="histogram"> <xsl:param name="path" /> <xsl:for-each select="$path"> <xsl:value-of select="@value"/> </xsl:for-each> </xsl:template>
<xsl:call-template name="histogram"> <xsl:with-param name="path" select="'/report/histo/bar'" /> </xsl:call-template>
my XML looks like . <report> <histo> <bar value="20" /> <bar value="30" /> <bar value="40" /> <bar value="50" /> </histo>
</report>
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