RE: [xsl] for-each order

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

> 
> Hello,
> Is there a way to do <xsl:for-each ..... and looping backwards.

As it happens, there is.
<xsl:sort select="position()" data-type="number" order="descending"/>

It's actually a good conformance test for your processor!

Mike Kay
> 
> My XML looks like 
> <histo>
>    <bar value="60" legend="Jan" />
>    <bar value="77" legend="Feb" />
>    <bar value="53" legend="Mar" />
>    <bar value="14" legend="Apr" />
> </histo>
> 
> and I want to store 14,53,77,60 in a variable .
> 
> 
> <xsl:variable name="position">
>    <xsl:for-each select="$path">
>       <xsl:value-of select="@value"/>,
>    </xsl:for-each>
> </xsl:variable>
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list