Subject: RE: [xsl] for-each order From: "Long Zhao" <LZhao@xxxxxxxxxxxxxxxx> Date: Fri, 14 Dec 2001 11:34:19 -0600 |
how about this <xsl:variable name="position"> <xsl:for-each select="$path"> <xsl:value-of select="concat(@value, position)"/>, </xsl:for-each> </xsl:variable> Long -----Original Message----- From: Charly [mailto:cohana@xxxxxxxxxxxxxxx] Sent: Friday, December 14, 2001 2:35 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] for-each order Hello, Is there a way to do <xsl:for-each ..... and looping backwards. My XML looks like <histo> <bar value="60" legend="Jan" /> <bar value="77" legend="Feb" /> <bar value="53" legend="Mar" /> <bar value="14" legend="Apr" /> </histo> and I want to store 14,53,77,60 in a variable . <xsl:variable name="position"> <xsl:for-each select="$path"> <xsl:value-of select="@value"/>, </xsl:for-each> </xsl:variable> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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