Subject: RE: [xsl] Simplest way to return an empty node-set From: "Oleg Tkachenko" <olegt@xxxxxxxxxxxxx> Date: Fri, 28 Dec 2001 08:57:42 +0200 |
It's classic /.. expression - parent of the root node. --- Oleg Tkachenko, Multiconn International, Israel > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Brian Smith > Sent: Friday, December 28, 2001 8:27 AM > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Simplest way to return an empty node-set > > > What is the simplest XPath expression that is guarenteed to generate an > empty node-set in an doucment? I sometimes need to return an empty > node-set from an function using the EXSLT functions module. Returning an > empty string (the default return value for an EXSLT function) does not > work for me. > > I would think there would be a really simple expression for the empty > node-set, but I can't find it. I've thought of using "self::*[2]", > self::*[not(.)]" and "self::*[. != .]" but those seem rather hack-ish. > > Any suggestions? > > Thanks, > Brian > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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