RE: local-name() namespace xslt 2.0 question was Re: [xsl] Identity transformation (without using xsl:copy)

["Bryan Rasmussen" <bry@xxxxxxxxxx>]

>> <xsl:param name="name"
>> select="concat(substring-before(name(),':'),local-name())"/>
>> <xsl:element name="{$name}">

>concat(substring-before(name(),':'),local-name())

>will return the same value as

>name()
actually that one won't, it was my booboo, <xsl:param name="name"
select="concat(substring-before(name(),':'),':',local-name())"/> will
produce the same as name()
this is because the original thread Re: [xsl] Identity transformation
(without using xsl:copy) wanted to copy nodes(including namespace nodes)
without using xsl:copy.

>There isn't a function to extract the prefix, because it's not usually
>significant, but there is a function namespace-uri() to get the
>corresponding namespace URI.

yeah I forgot namespace-uri(), and I agree it's not generally significant,
but for some reason they wanted to copy a namespace node without xsl:copy,
which this did, in msxml 4 at least, then when I did it I thought: "there
must be a simpler way to do this, without using xsl:copy of course"



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