Subject: Re: [xsl] Getting Attribute names in an XML with XSLT stylesheet From: jon budar-danoff <jbudardanoff@xxxxxxxxx> Date: Tue, 9 Apr 2002 12:18:33 -0700 (PDT) |
Jeni wrote, in answer to Morgan's question: > > You can get the name of any node (including attributes) using the > name() function. Pass the node as the argument to the name() > function, or don't pass any arguments if you want to use the context > node: > > <xsl:template match="@*"> > <xsl:value-of select="name()"/> > </xsl:template> I was just struggling with very much the same problem when I decided to check the (digested) list. Problem solved -- thanks, Jeni (and Morgan for asking the question)! ===== ----------------------------------------------------------------------- In walking, just walk. In sitting, just sit. Above all, don't wobble. -- Yun-Men __________________________________________________ Do You Yahoo!? Yahoo! Tax Center - online filing with TurboTax http://taxes.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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