Re: [xsl] next sibling

Subject: Re: [xsl] next sibling
From: "Carmelo" <carmelo@xxxxxxxx>
Date: Tue, 23 Apr 2002 11:29:12 -0400
Also make sure you want to use "*".  Perhaps you wish to refine
your searh a bit more and use the element name.

Carmelo
----- Original Message ----- 
From: "Brinkman, Theodore" <Theodore.Brinkman@xxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, April 23, 2002 9:44 AM
Subject: RE: [xsl] next sibling


> I'm an XSLT newbie, but I think if you did <xsl:for-each
> select="*[@testParam = 'yes']"> it would work.
> 
> Somebody correct me if I'm wrong.
> 
> - Theo
> 
> -----Original Message-----
> From: Lea Allison [mailto:Lea.Allison@xxxxxxxxxxxxxx]
> Sent: Tuesday, April 23, 2002 9:34 AM
> To: XSL List (E-mail)
> Subject: [xsl] next sibling
> 
> 
> Hi
> 
> I am looking for away to jump to the next node in a for-each loop. eg:
> 
> 
> for-each select="*"
> 
> choose
> when test="@testParam = 'yes' "
> DO THIS
> 
> otherwise
> skip to next node where @testParam = 'yes' and DO
> THIS
> 
> /choose
> /for-each
> 
> 
> Hope someone can help out
> 
> Thanks
> 
> Lea
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


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