[xsl] accessing last element of node set passed as parameter

["paul morgan" <pmorg@xxxxxxxxx>]

I'm trying to figure out how to access the last element of a node set which is passed as a parameter to a template.

For example, with:

    <xsl:template match="FOO">
        <xsl:param  name="result"  select="/.." />
        <xsl:variable  name="prior"  select="$result/BAR[last()]" />
        <!-- Something done it is -->
    </xsl:template>

if "FOO" is matched, and the parameter, "result", is assigned the node set

    <BAR i=1/><BAR i=2/><BAR i=3/>

what expression would I need to access the last "BAR" element (note, I will not always know that the last element has the attribute, 'i' equal to 3).  I tried many things and I thought "$result/BAR[last()]" might be a winner, but (alas) it is not.

Thanks,

Paul



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