Re: [xsl] accessing last element of node set passed as parameter

Subject: Re: [xsl] accessing last element of node set passed as parameter
From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Date: Mon, 20 May 2002 23:44:17 +0200
paul morgan wrote:
I'm trying to figure out how to access the last element
> of a node set which is passed as a parameter to a template.

For example, with:


    <xsl:template match="FOO">
        <xsl:param  name="result"  select="/.." />
        <xsl:variable  name="prior"  select="$result/BAR[last()]" />
        <!-- Something done it is -->
    </xsl:template>

if "FOO" is matched, and the parameter, "result", is assigned the node set

<BAR i=1/><BAR i=2/><BAR i=3/>

what expression would I need to access the last "BAR" element

You are trying to select the last of BAR *children* of anything in the passed node set. Try select="$result[last()]", though I'm not sure it'll work either.

J.Pietschmann


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