AW: [xsl] Counting number of characters of sibling text node

["Fries, Markus, fiscus GmbH, Bonn" <M.Fries@xxxxxxxxxxx>]

Try        <xsl:value-of select="$pastTxtLen + string-length(.)" />
instead of <xsl:value-of select="string-length($pastTxtLen) +
string-length(.)" />

If it does not work there is yet another (whitespace) problem.


-----Ursprüngliche Nachricht-----
Von: Filipe Correia [mailto:filipe.correia@xxxxxxxxxxxxxxx]
Gesendet: Mittwoch, 22. Mai 2002 14:26
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: [xsl] Counting number of characters of sibling text node


What I want to do is to count the number os characters in a  text node and
all previous text nodes children of the current text node's parent.

           parent
              |
  ----------------------------
  |        |        |         |
text1 <br/>  text2  <br/>


  When having text1 has the current node my template would return the number
of characters of text1 but when having text2 has the current node my
template would return the sum of number of characters of text1 with number
of characters of text2.

  I've tried using the following template:

<xsl:template match="text()" mode="getStrLen">
   <xsl:variable name="pastTxtLen"><xsl:apply-templates
select="preceding-sibling::text()[1]" mode="getStrLen"/></xsl:variable>
   <xsl:value-of select="string-length($pastTxtLen) + string-length(.)" />
</xsl:template>

I get it's result by doing: 
<xsl:variable name="pastTxtLen"><xsl:apply-templates select="."
mode="getStrLen"/></xsl:variable>

Doing it this way I get the rong result.
For the example above, when I have text1 has the current node it works
fine(the number of characters of text1 only is returned) but when I have
text2 has the current node a rong result.

   Any suggestions?

      Filipe


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