Subject: RE: [xsl] Grouping and Sorting on value inside group From: "Hunsberger, Peter" <Peter.Hunsberger@xxxxxxxxxx> Date: Tue, 11 Jun 2002 17:13:18 -0500 |
>>I finally found the answer. Your use of [@dataid = current()/@dataid] >>provided the missing clue: >> >> <xsl:for-each select="(//dataset/*/*[generate-id() = >>generate-id(key('dataids', concat(local-name(..),@dataId)))])"> >> <xsl:sort select="parent::node()/*[local-name() = $sortcol and >>@dataId = current()/@dataId]/value"/> > >... > >The expression > > (//dataset/*/*[generate-id() = > generate-id(key('dataids', concat(local-name(..),@dataId)))]) > > would seem on the face of it to find the same node as > > key('dataids', concat(local-name(..),@dataId))[1] > > since the node inside any dataset that has the same generated ID as the > first node in the set returned by the key expression, is that node (or > nothing). Yah, but since it's in a for-each I'm not just looking at the first node? > What am I missing? (I admit I'm looking at this thread late.) You might not be missing anything, but the code does what I expect, so I may not be explaining everything properly... XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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