RE: [xsl] Grouping and Sorting on value inside group

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Peter,

I hope we're not just repeating things over the back fence, but....

At 09:36 AM 6/12/2002, you wrote:
> > That would be so, except the generate-id() function has already filtered
> > out all but the first of the nodes returned by the key() function.... it
> > only operates on the first node in the set, when its argument is a node
> set
> > (since it returns a string, it has to pick one node and that's the one it
> > picks).
>
> That makes sense.  My understanding is that I'm picking up the context of
> the nodes in the for-each and comparing the first nodes of each group
> matching the respective dataIds (there are multiple groups of nodes each
> with a different dataId).  This may be a ambiguity or even bug, the key
> reference should probably make it explicit?

It's not the key() function that's reducing it to a single node, it's the 
generate-id() function you are running on the nodes returned by key(). As in:

"The generate-id function returns a string that uniquely identifies the 
node in the argument node-set that is first in document order." [XSLT 12.4]

No ambiguity there. Beyond this, I think Tom S. explained it.

But I'm confused not having the examples in front of me. Would you be able 
to snip them out (again) and recapitulate the question if I'm not getting 
what you're asking?

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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