Subject: [xsl] linkdiff template From: Guy McArthur <guym@xxxxxxxxxxxxxxx> Date: Wed, 12 Jun 2002 17:19:08 -0700 (MST) |
Hi, I'm looking to write a template to output the a/@href's from one (newer) file that are *not* present in another (older) file. I.e. given the following two files -old.xml- <html> <a href="http://www.google.com/>Google!</a> <a href="http://w3.org/">W3C</a> </html> -new.xml- <html> <a href="http://w3.org/">W3C</a> <a href="http://guymcarthur.com">My HomePage</a> <a href="http://xml.apache.org/xalan/">Xalan</a> </html> -- The output would be: http://guymcarthur.com http://xml.apache.org/xalan/ Here's my first stab at the stylesheet: -linkdiff.xsl- <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="previous"/> <xsl:key name="links" match="a" use="document($previous)///a/@href"/> <xsl:output method="text"/> <xsl:template match="a"> <xsl:if test="not(boolean(key('links', @href)))"> <xsl:value-of select="@href"/> </xsl:if> </xsl:template> </xsl:stylesheet> -- However, it is just outputting all the href's (test is always true). Please enlighten me! I'm using 'java org.apache.xalan.xslt.Process -IN new.xml -XSL \ linkdiff.xsl -PARAM previous old.xml'. GKM XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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