Re: [xsl] linkdiff template

On Thu, 13 Jun 2002, Joerg Heinicke wrote:

> Sorry, a litle mistake. It has to be
> 
> <xsl:for-each select="document($previous)">
> 
> of course.
> 

I thought I understood, but I get an "unknown error in XPath" on line 12.
Here is the xsl I'm using: (also tried putting wrapping the key() method 
with a boolean() method.
--
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:param name="previous"/>

 <xsl:key name="links" match="a" use="@href"/>

 <xsl:output method="text"/>

 <xsl:template match="a">
  <xsl:variable name="href" select="@href"/>
  <xsl:for-each select="document($previous)">
   <xsl:if test="not(key('links', $href))">
     <xsl:value-of select="$href"/>
   </xsl:if>
  </xsl:for-each>
 </xsl:template>

</xsl:stylesheet>
--

Also, it would seem by looking at it, that it would walk through all the 
elements of document($previous) for every matching "a" element. Shouldn't 
building a key eleminate the need to walk through the tree each time?

Guy

> 
> Joerg Heinicke wrote:
> > A key in XSLT is always created for every XML-tree. So you don't need a 
> > document() in the key's use-attribute. With your declaration the key of 
> > the indexed links is always the value of the first a/@href in $previous.
> > 
> > <xsl:key name="links" match="a" use="@href"/>
> > 
> > <xsl:param name="previous"/>
> > 
> > <xsl:template match="a">
> >   <xsl:variable name="href" select="@href"/>
> >   <xsl:for-each select="$previous">
> >     <xsl:if test="not(key('links', $href))">
> >       <xsl:value-of select="$href"/>
> >     </xsl:if>
> >   </xsl:for-each>
> > </xsl:template>
> > 
> > Regards,
> > 
> > Joerg
> > 
> > Guy McArthur wrote:
> > 
> >> Hi, I'm looking to write a template to output the a/@href's from one 
> >> (newer) file that are *not* present in another (older) file.
> >>
> >> I.e. given the following two files
> >> -old.xml-
> >> <html>
> >>  <a href="http://www.google.com/>Google!</a>
> >>  <a href="http://w3.org/";>W3C</a>
> >> </html>
> >> -new.xml-
> >> <html>
> >>  <a href="http://w3.org/";>W3C</a>
> >>  <a href="http://guymcarthur.com";>My HomePage</a>
> >>  <a href="http://xml.apache.org/xalan/";>Xalan</a>
> >> </html>
> >> -- 
> >> The output would be:
> >> http://guymcarthur.com
> >> http://xml.apache.org/xalan/
> >>
> >> Here's my first stab at the stylesheet:
> >> -linkdiff.xsl-
> >> <xsl:stylesheet version="1.0" 
> >> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> >>
> >>  <xsl:param name="previous"/>
> >>
> >>  <xsl:key name="links" match="a" use="document($previous)///a/@href"/>
> >>  
> >>  <xsl:output method="text"/>
> >>
> >>  <xsl:template match="a">
> >>    <xsl:if test="not(boolean(key('links', @href)))">
> >>      <xsl:value-of select="@href"/>
> >>    </xsl:if>
> >>  </xsl:template>
> >>
> >> </xsl:stylesheet> --
> >>
> >> However, it is just outputting all the href's (test is always true).
> >> Please enlighten me!
> >>
> >> I'm using 'java org.apache.xalan.xslt.Process -IN new.xml -XSL \
> >> linkdiff.xsl -PARAM previous old.xml'.
> >>
> >> GKM
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

-- 
--
Guy McArthur * email{guym@xxxxxxxxxxx} http{guymcarthur.com}      
LPL Rm. #538 * w{520-621-6373} h{520-326-4555} icq{17470307} 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
<- Previous	Index	Next ->
Re: [xsl] linkdiff template, Joerg Heinicke	Thread	Re: [xsl] linkdiff template, Joerg Heinicke
Re: [xsl] selecting an element in a, Jarkko . Moilanen	Date	Re: [xsl] Template priority, Peter Davis
	Month
<-prev [Thread] next->	<-prev [Date] next->
Month Index \| List Home