Re: [xsl] Reference to other node

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

Andrew Welch wrote:
> <xsl:variable name="id-found"
> select="generate-id(//GrilleSimple[local-name()=$name-to-find])"/>

Sorry Andrew,

but it should be

select="generate-id(//GrilleSimple[@Nom = $name-to-find])"

Alexandre,

it's maybe better to set up a key or at least to remove // from your XPATH:


<xsl:key name="gs" match="GrilleSimple" use="@Nom"/>

later in a template:
<xsl:variable name="id-found" select="generate-id(key('gs', 
$name-to-find))"/>

It does the same, but it's much faster, because the <GrilleSimple/>s are 
indexed and the file won't be searched every time.

Regards,

Joerg

> -----Original Message-----
> From: alexandre bord [mailto:alexandre.bord@xxxxxxxxxx]
>
> How could i better do that ?  :
>
> <fo:block>
> <xsl:variable name="id-found"><xsl:for-each 
> select="//GrilleSimple[@Nom=$name-to-find]">
>     <xsl:value-of select="generate-id()"
> /></xsl:for-each></xsl:variable>
>                 This is on page    <fo:page-number-citation 
> ref-id="{$id-found}" />
> </fo:block>
>
>
> * name-to-find is a variable
> * xsl:for-each returns only one node
>
> Thanks a lot.
> Alexandre


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