Re: [xsl] RE: how I can select the largest attribute value

["Vasu Chakkera" <vasucv@xxxxxxxxxxx>]

That will not serve the purpose...
u have to select the first among the sorted..
so the following code would help...

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:for-each select="/Root/element">
<xsl:sort order="descending" select="@length" data-type="number"/>
<xsl:if test="position()=1">
<xsl:value-of select="@length"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

hope this help
Vasu


> From: Henk Meulekamp <henkm@xxxxxxx>
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Subject: [xsl] RE: how I can select the largest attribute value
> Date: Tue, 18 Jun 2002 16:35:22 +0200
>
>
> Maybe you can do something like this?
>
> <xsl:for-each select="Root/element[1]">
> 	<xsl:sort select="@length" data-type="number" order="descending"/>
> 		<xsl:value-of select="@length"/>
> </xsl:for-each>
>
> | -----Original Message-----
> | From: Bodrul Haque [mailto:Bodrul.Haque@xxxxxxxxxxxxxxxxxxxxxxx]
> | Sent: dinsdag 18 juni 2002 16:23
> | To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> | Subject:
> |
> |
> | Hi List,
> |
> | Can someone please tell me how I can select the largest
> | attribute value from the following xml file, without doing
> |
> | <xsl:value-of select="Root/element[@length="14"]/@length" />.
> |
> | (I don't want to use a hard coded value in the predicate). Is
> | there an Xpath that i can use. Xml file: <Root>
> |      <element  length="3" />
> |      <element  length="14" />
> |      <element  length="1" />
> |      <element  length="6" />
> |      .....
> | </Root>
> |
> | I'm using MSXML3.
> |
> | Thanks in Advance
> |
> | Bodrul
> |
> |
> |
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