Re: [xsl] How to get and display part of XML document in IE5/6?

["Qinghui Zeng" <zengqh@xxxxxxx>]

> > " english.xml#xpointer(/document/language/page(id=1)) "
>
> To make it short:
>
> <xsl:value-of
> select="document('english.xml')/document/language/page[@ID=1]"/>
>

That's fine to fetch the part content with this method,  but still
a problem is how to pass the parameter(e.g. ID=1)  to stylesheet.
In detail, I have five xml files, each for one language(English,
German,...),
and each includes some pages.
---------------------------------
<Doc lang=EN>
    <Pages>
        <Page ID=1>.....</Page>
        ......
        <Page ID=1>.....</Page>
    </Pages>
</Doc>
---------------------------------
Assume, Page 1 is displayed in IE, now I want to display Page 5 by a link,
Considering compatibility with future fully xml-supported explorer, (right?)
 In page 1(source), I use such a link :
" english.xml#xpointer(/Doc/Pages/Page(ID=5)) "
but I don't know how  I  can pass "ID=5" to the template in XSL?
Or I need use other link method ?

Thanks.

Qinghui



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