Subject: Re: [xsl] The operator '!=' returns false when one operand doesn't exist From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx> Date: Wed, 07 Aug 2002 18:02:08 +0000 |
From: Jerome Louvel <jerome_louvel@xxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] The operator '!=' returns false when one operand doesn't exist
Date: Wed, 7 Aug 2002 08:32:17 -0700 (PDT)
Hi All,
We have an issue with the XPath '!=' operator that has a strange behavior when one of its operand doesn't exist in the instance document. It returns 'false" when you would expect "true" or some kind of exception to be raised.
Sample stylesheet: ------------------ <?xml version="1.0" encoding="UTF-8"?> <xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <data> <xsl:value-of select="/data/a != /data/b"/> </data> </xsl:template> </xsl:transform>
Instance: --------- <?xml version="1.0"?> <data> <a>10</a> </data>
This transformation will return 'false'. If you add <b>11</b> under element a, or even an empty <b/>, the result is becoming 'true'.
Could somebody explain me why we get such a result (with MSXML 4.0 as well as Xalan)? Is there a simple way, extension function or XPath expression to would make this work as "expected" (true is one of this operand doesn't exist)?
Thanks for your help! Jerome.
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