Re: [xsl] The operator '!=' returns false when one operand doesn't exist

[Michael Fuller <msf@xxxxxxxxxxxxxxx>]

Jerome Louvel wrote:
> We have an issue with the XPath '!=' operator [...]

As others have observed, this is the defined behaviour for nodesets.

For example, given the nodesets
    NS1: {<a>-1</a>, <b>0</b>, <c>1</c>}
and
    NS2: {<X>0</X>}

this means that all of the following relationships hold:

    NS1 = NS2   (the string value of the node <X>0</X> in the second set
                 is equal to the string value of the node <b>0</b>)

    NS1 != NS2  (the string value of the node <X>0</X> in the second set
                 is not equal to the string value of the node <a>-1</a>)

    NS1 < NS2   (the string value of the node <X>0</X> in the second set
                 is > the string value of the node <a>-1</a>)

    NS1 > NS2   (the string value of the node <X>0</X> in the second set
                 is < the string value of the node <c>1</c>)

    NS1 >= NS2  (the string value of the node <X>0</X> in the second set
                 is >= the string value of the node <b>0</b>)

    NS1 <= NS2  (the string value of the node <X>0</X> in the second set
                 is >= the string value of the node <b>1</b>)
!!


:-)

Enjoy.

Michael

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