Subject: Re: [xsl] generalized unique element From: "Laura Jenkins" <xsl_list@xxxxxxxxxxx> Date: Wed, 11 Sep 2002 14:09:37 +0000 |
Thanks david that was superb, as u had suggested I tried using the keys and was successful ( i referred to jeni's article ) the following is what i did.. <xsl:key match="*" use="name(.)" name="all-nodes"/> .. ... .... ..... ...... <xsl:if test="count(.| key('all-nodes', name(.))[1]) = 1">
It works fine, i however do not understand what goes on in the above line.. I would be thankful if u can please explain me the 1.use of count in the above statement. 2.especially the use of key('',xx)[1] above ..
same with doing <xsl:if test="generate-id() = generate-id(key('all-nodes', name(.)[1])"> i understand the use of generate-id() but do not understand key('',xx)[1]
From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] generalized unique element Date: Wed, 11 Sep 2002 14:40:19 +0100
tried doing something like.. <xsl:if test="not(name(.) = preceding::node()/name())">
the / operator has to have path expressions not functions that return a string, like name(). You want the second name() to be like te first, taking the node as argument.
name(preceding::node())
unfortunately you then can't use the magic property of = to test all elements of a node set, so you then need to use a predicate,something like
<xsl:variable name="n" select="name(.)"/> <xsl:if test="preceding::*[name(.)=$n]">
You mentioned though the "Meunchian method" which does the same using keys which will be quicker on large data sets
David
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