Subject: RE: [xsl] Can you apply a template match on a copy node? From: "Dion Houston" <dionh@xxxxxxxxxxxxxxxxxxxxx> Date: Wed, 18 Sep 2002 15:26:20 -0700 |
Hi Mike! I would strongly advise you to rework the problem, as there is no (IMHO) clean way to do what you want to do. The following will work: <xsl:variable name="myNode"> <xsl:copy> <xsl:apply-templates .../> </xsl:copy> </xsl:variable> <xsl:apply-templates select="vendor:node-set($myNode)"/> Where vendor:node-set() is the implementation specific function to convert an RTF to a node set. Most problems like this can be solved in better ways, though... HTH! Dion -----Original Message----- From: Mike Carlisle [mailto:swflash@xxxxxxxxxxx] Sent: Wednesday, September 18, 2002 3:09 PM To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Can you apply a template match on a copy node? Hello list people, Wonder if anyone can help. I have an xsl which is applying templates on match. One of these templates matches on an attribute. For various reasons within this template I want to copy the node (filtering out the matched attribute), and then apply templates to the copy of this node. How can I reference this copy? So far I have only been able to apply attribute matches to my new node, not node matches. Here's my code. It needs to write out the contents of the title attribute, make a copy of the node without the title attribute, and then apply templates to this new copy. <xsl:template match="*[@title]"> <xsl:value-of select="@title" /> <xsl:copy> <xsl:apply-templates select="node()|@*[not(name(.) = 'title')]" /> </xsl:copy> </xsl:template> Any help is much appriecated. Mike XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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