[xsl] Re: Selecting a random node from source-tree

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

"Martin Lormes" <martin dot lormes at gmx dot net> wrote:

> In XSLT 1.0

> How do I select a random node from the source-tree or from an
external
> document?
> I was thinking of an XPath expression like this:
> 
> document('funnies.xml')/funnies/quote[random()]
> 
> Can I avoid using extension elements?

Yes, use the "randNext" template from FXSL.

More information is contained in the article: 

"Casting the Dice with FXSL: Random Number Generation Functions in
XSLT"

http://fxsl.sourceforge.net/articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm

Hope this helped.



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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