Subject: [xsl] Simple Question concerning [last()] From: Stefan.Wachter@xxxxxx Date: Sat, 8 Feb 2003 19:19:30 +0100 (MET) |
Hi all. My question is about a [last()] predicate in a simple step. Running the following stylesheet on itself yields unexpected results using Saxon and Xalan. I thought the XPath ".//x[last()] should return the last x-Element in document order. However, it returns the first one. Changing the selection to ".//x[2] returns nothing at all! Yet, the XPath ".//x" returns all x-Elements and the first x-Element has the position 1 and the second 2. Is this a bug in the mentioned XSLT processors or have I missed something? Thanks for your attention, Stefan Wachter <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:message> <xsl:for-each select=".//x[@u]"> <xsl:value-of select="concat(@u, '(', position(), ') ')"/> </xsl:for-each> </xsl:message> <xsl:message><xsl:value-of select=".//x[last()]/@u"/></xsl:message> <a> <x u="1"/> </a> <a> <x u="2"/> </a> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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