Subject: [xsl] Full path to a node From: Ronny Haryanto <ronnyharyanto@xxxxxxxxxxx> Date: Mon, 10 Feb 2003 10:20:15 +0700 |
Hi all, Is it possible to print out the full path of a node with XSL? Let say I have a menu.xml like the following for a web application's menu system: <menu href="/" label="Home"> <menu href="manage/" label="Manage"> <menu href="customer/" label="Customer"> <menu href="customer/register/" label="Register" /> <menu href="customer/" label="Query" /> </menu> <menu href="project/" label="Project"> <menu href="project/register/" label="Register" /> <menu href="project/" label="Query" /> </menu> <menu href="employee/" label="Employee"> <menu href="employee/register/" label="Register" /> <menu href="employee/" label="Query" /> </menu> </menu> </menu> When I view the "Register A Project" page in the web application I want to print out: Home :: Manage :: Project :: Register at the top of the page. I tried writing several XSLs but most of them got stuck in infinite recursive loop or prints only the root node or the "Project Register" node. I just started learning XSL 2 days ago so I'm still not used to thinking in terms of XPath and XSL. I would really appreciate any suggestions and/or pointers. Thanks. Ronny XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] Design question, XSLList | Thread | Re: [xsl] Full path to a node, Oleg Tkachenko |
RE: [xsl] Design question, XSLList | Date | Re: [xsl] preceding-sibling inside , Ted Stresen-Reuter |
Month |