Re: [xsl] Full path to a node

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

Ronny Haryanto wrote:

> Is it possible to print out the full path of a node with XSL?
Sure.


> When I view the "Register A Project" page in the web application I
> want to print out:
>
> 	Home :: Manage :: Project :: Register
>
> at the top of the page.

You can use ancestor-or-self axis to get full list of ancestors including 
self, then iterate through the list and output labels:

            <xsl:for-each select="ancestor-or-self::*/@label">
                <xsl:value-of select="."/>
                <xsl:if test="position() != last()">
                    <xsl:text> :: </xsl:text>
                </xsl:if>
            </xsl:for-each>

See also faq about getting pathes to a node: 
http://www.dpawson.co.uk/xsl/sect2/N6077.html#d5745e18

--
Oleg Tkachenko
Multiconn Technologies, Israel


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