Subject: RE: [xsl] Re: dynamic XPath? From: "Yue Ma" <MaY@xxxxxxxxxxxxxxxx> Date: Thu, 13 Mar 2003 10:02:16 -0500 |
First I thank all of your help here. :) Yes Tom, you got it correct about my original question: a literal XPath string eventually evaluated as node (node set) Maybe I didn't give enough or, clear enough information about my question, sorry about that. My colleague asked me that but I've never used "dynamic XPath" and I remember a while ago I may have read a post here said that we can not do it, but I wasn't so sure about that. I'll clarify with my colleague (maybe ask her to re-join this list :)) about it, but for now I agree with the answer that we actually need an evaluate() function and we don't have it in XSLT 1.0 and 2.0 except some special extensions. Thanks again! Yue >>> tpassin@xxxxxxxxxxxx 03/12/03 04:27PM >>> [Dimitre Novatchev] > > It will also "work" for more than one node (in case $tagPath > evaluates to a > nodeset of two or more nodes) and most probably is not what > the author of > the original message wanted. > I think I may have misunderstood here, and perhaps you misunderstood me as well... I understood the original question to ask for matching a __string__ containing a path expression, like "/a/b/c" (that is the kind of example O thought that Yue Ma showed). For my own post, I put the path string into a variable, thinking that it would probably eventually be sent in via a parameter. Re-reading your comment, I notice that you might have thought that I was selecting a node set into the variable, instead of a string, but that is not the case. Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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