RE: [xsl] use of xsl:key in cross-referencing

["Lars Huttar" <lars_huttar@xxxxxxx>]

Dear Xiaocun,

> To define two keys for the two groups with the same
> name but different "use":
> <xsl:key name="QuestionnaireKey" match=//row[@row &lt;
> 20]" use="string(cell[@column=2])"/>
> <xsl:key name="QuestionnaireKey" match=//row[@row &gt;
> 20]" use="string(cell[@column=1])"/>
>
> Use Muenchian method to process each just once, for
> the 2nd group:
> <xsl:apply-templates select="//row[@row &gt; 20 and
> @row &lt; 30][count(.|key('QuestionnaireKey',
> string(cell[@column=1]))[1]) = 1]"/>
> but this will miss questionnaire QC.

Huh?  I can see how it will miss questionnaire QB, but not QC.

> I guess to take advantage of the combined key, I need
> to do select on all rows, like:
> <xsl:apply-templates
> select="//row[count(.|key('QuestionnaireKey',
> string(cell[@column=1]))[1]) = 1]"/>
> Would the above work?

I don't think so, because it uses @column=1 for all rows,
instead of using @column=2 for the first group and @column=1
for the second group.

> If so, how can I tell if the
> row being processed is from group 1 (Questionnaire) or
> 2 (Question)?

Above, you had "@row &gt; 20 and @row &lt; 30".  Do you know
these boundary numbers in advance?  If so, why not use them.

Here's a select expression and template that should allow you to
process each Questionnaire once...

        <xsl:apply-templates select="/range/row[count(.|key('QuestionnaireKey',
                                     string(cell[@column=1 and
                                       ../@row &gt; 20] |
                                     cell[@column=2 and
                                       ../@row &lt; 20]))[1]) = 1]" />
...

  <xsl:template match="row">
    <p>
      <xsl:choose>
        <xsl:when test="@row &lt; 20">
          Processing Questionnaire <xsl:value-of select="cell[@column=2]" />
        </xsl:when>
        <xsl:otherwise>
          Processing Questionnaire <xsl:value-of select="cell[@column=1]" />
        </xsl:otherwise>
      </xsl:choose>
    </p>
  </xsl:template>

I tried this with your test data and it displayed 
	Processing Questionnaire QA
	Processing Questionnaire QB
	Processing Questionnaire QC

Does this solve your problem?

Lars


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