RE: [xsl] use of xsl:key in cross-referencing

[Xiaocun Xu <xiaocunxu@xxxxxxxxx>]

Dear Lars:

  Thank you for your reply, your solution is exactly
what I needed.  If creating a key with the same name
using two different groups that key off different
elements, then I need to use apply-templates
separately on the two different groups.  
  Also, you were right when you mention it will miss
QB instead of QC, must've been brain fart, argh!!

Thanks for the help, much appreciated.
Xiaocun

--- Lars Huttar <lars_huttar@xxxxxxx> wrote:
> Dear Xiaocun,
> 
> > To define two keys for the two groups with the
> same
> > name but different "use":
> > <xsl:key name="QuestionnaireKey" match=//row[@row
> &lt;
> > 20]" use="string(cell[@column=2])"/>
> > <xsl:key name="QuestionnaireKey" match=//row[@row
> &gt;
> > 20]" use="string(cell[@column=1])"/>
> >
> > Use Muenchian method to process each just once,
> for
> > the 2nd group:
> > <xsl:apply-templates select="//row[@row &gt; 20
> and
> > @row &lt; 30][count(.|key('QuestionnaireKey',
> > string(cell[@column=1]))[1]) = 1]"/>
> > but this will miss questionnaire QC.
> 
> Huh?  I can see how it will miss questionnaire QB,
> but not QC.
> 
> > I guess to take advantage of the combined key, I
> need
> > to do select on all rows, like:
> > <xsl:apply-templates
> > select="//row[count(.|key('QuestionnaireKey',
> > string(cell[@column=1]))[1]) = 1]"/>
> > Would the above work?
> 
> I don't think so, because it uses @column=1 for all
> rows,
> instead of using @column=2 for the first group and
> @column=1
> for the second group.
> 
> > If so, how can I tell if the
> > row being processed is from group 1
> (Questionnaire) or
> > 2 (Question)?
> 
> Above, you had "@row &gt; 20 and @row &lt; 30".  Do
> you know
> these boundary numbers in advance?  If so, why not
> use them.
> 
> Here's a select expression and template that should
> allow you to
> process each Questionnaire once...
> 
>         <xsl:apply-templates
> select="/range/row[count(.|key('QuestionnaireKey',
>                                     
> string(cell[@column=1 and
>                                        ../@row &gt;
> 20] |
>                                      cell[@column=2
> and
>                                        ../@row &lt;
> 20]))[1]) = 1]" />
> ...
> 
>   <xsl:template match="row">
>     <p>
>       <xsl:choose>
>         <xsl:when test="@row &lt; 20">
>           Processing Questionnaire <xsl:value-of
> select="cell[@column=2]" />
>         </xsl:when>
>         <xsl:otherwise>
>           Processing Questionnaire <xsl:value-of
> select="cell[@column=1]" />
>         </xsl:otherwise>
>       </xsl:choose>
>     </p>
>   </xsl:template>
> 
> I tried this with your test data and it displayed 
> 	Processing Questionnaire QA
> 	Processing Questionnaire QB
> 	Processing Questionnaire QC
> 
> Does this solve your problem?
> 
> Lars
> 


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