Re: [xsl] xpath question

Subject: Re: [xsl] xpath question
From: florian <csshsh@xxxxxxxxxxxxxxx>
Date: 27 Mar 2003 18:41:02 +0100
ah! i think i figured it out:

i wonder if there is a more nice way though

group/*[local-name() = $field]

i set the field variable to the field attribute
of the column node. is there a more elegant
way though?

ciao!
florian




On Don, 2003-03-27 at 18:07, florian wrote:
> hi!
> 
> i have a document xml doc like this:
> 
> <root>
>   <group>
>      <apple>bla</apple>
>      <orange>bla</orange>
>   </group>
>   <group>
>      <apple>bla</apple>
>      <orange>bla</orange>
>   </group>
> 
>   <order>
>     <column name="orange" />
>     <column name="apple" />
>   </order>
> </root>
> 
> i would like to do the following: im going though all the column nodes
> and would like to access the group nodes where the column attribute name
> and the group node name match up.
> 
> basically i can just not think of a way to do that in xpath.. anybody
> got an tip? how can i say in xpath that it should get the node with
> the name in @name and not just access the name attribute of a group
> node..
> 
> thanks alot!
> 
> ciao!
> florian
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread