Re: [xsl] strange <br/> tag

[Mike Brown <mike@xxxxxxxx>]

Karl J. Stubsjoen wrote:
> Hello,
> I have a stylesheet that has <br/> command(s) in it (of course).  I
> transform an xml document persisted from an ado recordset with this
> stylesheet.  When I view the source, the <br/> tag looks like this:
> 
> <br xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
> xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
> xmlns:rs="urn:schemas-microsoft-com:rowset" xmlns:z="#RowsetSchema">
> 
> Weird!  What is going on?
> Karl
> 
> XSL SOURCE:
> <!DOCTYPE xsl:stylesheet [
> <!ENTITY nbsp "&#160;">
> ]>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>       xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
>       xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
>       xmlns:rs="urn:schemas-microsoft-com:rowset"
>       xmlns:z="#RowsetSchema">

The stylesheet is treated as a node tree just like the XML source doc. So
every element in the stylesheet has a namespace node for each of the bindings
for prefixes xml, xsl, s, dt, rs, and z. When you put <br/> in your
stylesheet, that element has all those namespace nodes associated with it.
When you the element is copied into the result tree, as all literal result
elements are, all the namespace nodes go along with it. When it's time to
serialize the result tree, the processor is going to ignore the xml and xsl
bindings but will be keeping track of the rest, and outputting xmlns attrs
as needed.

Use exclude-result-prefixes="s dt rs z" in your xsl:stylesheet to suppress the
serialization behavior. Or use xsl:element instead of a literal result
element, to avoid the namespace nodes being copied over. Most processors don't
actually implement namespace nodes as such, though, so the first option is
probably better all around.

Mike

-- 
  Mike J. Brown   |  http://skew.org/~mike/resume/
  Denver, CO, USA |  http://skew.org/xml/

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