[xsl] position() returns doubled result - what do i miss?

[jian <jian@xxxxxxxxxxxxxxxxxx>]

i have :

<?xml version="1.0" encoding="UTF-8" ?>
<root>
      <item>item1</item>
      <item>item2</item>
      <item>item3</item>
      <item>item4</item>
      <item>item5</item>
      <item>item6</item>
      <item>item7</item>
      <item>item8</item>
      <item>item9</item>
</root>



to which i apply:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">

<xsl:output method="html" version="4.01" encoding="UTF-8"/>

 <xsl:template match="/">
   <xsl:apply-templates match="root/item"/>
 </xsl:template>

 <xsl:template match="item">
   <xsl:value-of select="position()"/>
   <xsl:value-of select="."/>
 </xsl:template>

</xsl:stylesheet>


and for some reason i get :

      2item1
      4item2
      6item3
      8item4
      10item5
      12item6
      14item7
      16item8
      18item9

what do i miss?

jian

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