Subject: Re: [xsl] position() returns doubled result - what do i miss? From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx> Date: Mon, 31 Mar 2003 22:18:49 +0200 |
i have :
<?xml version="1.0" encoding="UTF-8" ?> <root> <item>item1</item> <item>item2</item> <item>item3</item> <item>item4</item> <item>item5</item> <item>item6</item> <item>item7</item> <item>item8</item> <item>item9</item> </root>
to which i apply:
<?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" version="4.01" encoding="UTF-8"/>
<xsl:template match="/"> <xsl:apply-templates match="root/item"/> </xsl:template>
<xsl:template match="item"> <xsl:value-of select="position()"/> <xsl:value-of select="."/> </xsl:template>
</xsl:stylesheet>
and for some reason i get :
2item1 4item2 6item3 8item4 10item5 12item6 14item7 16item8 18item9
what do i miss?
Which processor are you using? Both saxon and msxml produce 1item12item23item34item45item56item67item78item89item9
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