Subject: RE: [xsl] name() of root element From: "Passin, Tom" <tpassin@xxxxxxxxxxxx> Date: Tue, 1 Apr 2003 10:52:42 -0500 |
[ joseph.a.gilvary@xxxxxxxxxx] > > Why does this not select the name of the root *element* but > instead gives me the text value of that element, i.e., the > concatenated text values of every element in my document? > > <xsl:template match="/" > > <xsl:value-of select="(/node()[1])[name()]" /> > <xsl:apply-templates /> > </xsl:template> > You have asked for the string value of the first child node that also has a name (more accurately, those members of {the set of the first child element} that have a name). You got what you asked for. What you really had in mind is probably select='name(node())' Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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