RE: [xsl] name() of root element

Subject: RE: [xsl] name() of root element
From: "Passin, Tom" <tpassin@xxxxxxxxxxxx>
Date: Tue, 1 Apr 2003 10:52:42 -0500
[ joseph.a.gilvary@xxxxxxxxxx] 
> 
> Why does this not select the name of the root *element* but 
> instead gives me the text value of that element, i.e., the 
> concatenated text values of every element in my document?
> 
>     <xsl:template match="/" >
>         <xsl:value-of select="(/node()[1])[name()]" />
>         <xsl:apply-templates />
>     </xsl:template>
> 

You have asked for the string value of the first child node that also
has a name (more accurately, those members of {the set of the first
child element} that have a name).  You got what you asked for.  

What you really had in mind is probably

select='name(node())'

Cheers,

Tom P

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