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Subject: RE: [xsl] name() of root element From: "Passin, Tom" <tpassin@xxxxxxxxxxxx> Date: Tue, 1 Apr 2003 10:52:42 -0500 |
[ joseph.a.gilvary@xxxxxxxxxx]
>
> Why does this not select the name of the root *element* but
> instead gives me the text value of that element, i.e., the
> concatenated text values of every element in my document?
>
> <xsl:template match="/" >
> <xsl:value-of select="(/node()[1])[name()]" />
> <xsl:apply-templates />
> </xsl:template>
>
You have asked for the string value of the first child node that also
has a name (more accurately, those members of {the set of the first
child element} that have a name). You got what you asked for.
What you really had in mind is probably
select='name(node())'
Cheers,
Tom P
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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