Subject: RE: [xsl] 10,000 document()'s From: "Bhandari, Ashish" <Ashish.Bhandari@xxxxxx> Date: Tue, 8 Apr 2003 12:37:55 -0400 |
How about writing your own extension function to do that - a user defined extension function which would make a system call to determine the number of lines or any such information you may want given a file name. -----Original Message----- From: Peter Binkley [mailto:Peter.Binkley@xxxxxxxxxxx] Sent: Tuesday, April 08, 2003 12:06 PM To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx' Subject: [xsl] 10,000 document()'s I need advice on how to tackle this problem: I've got a file that contains a list of about 10,000 other files, and I want to process the list so as to add a wordcount for each of the external files. Something like this: Input: <files> <file> <filename>/path/to/file/2844942.xml</filename <file> <file> .... </file> <files> Output: <files> <file> <filename>/path/to/file/2844942.xml</filename <wordcount>2938</wordcount> <file> <file> .... </file> <files> The obvious approach is to use a for-each loop that includes a variable that opens the external file using a document() call. The problem is that the process inevitably runs out of memory, both with Saxon and Xalan. It seems that the variables are passing out of scope and being destroyed as they should, but I gather from a posting by Michael Kay (http://www.biglist.com/lists/xsl-list/archives/200212/msg00507.html) that all of those document() source trees are remaining in memory throughout the transformation, adding up to megabytes of data. Can anyone suggest a strategy? The process doesn't have to be fast, it just has to finish. Peter Binkley Digital Initiatives Technology Librarian Information Technology Services 4-30 Cameron Library University of Alberta Libraries Edmonton, Alberta Canada T6G 2J8 Phone: (780) 492-3743 Fax: (780) 492-9243 e-mail: peter.binkley@xxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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