Re: [xsl] XSL to XSLT conversion issue

Subject: Re: [xsl] XSL to XSLT conversion issue
From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Date: Tue, 15 Apr 2003 22:37:11 +0200
Jim Hart wrote:
I want to convert:

[ index() $gt$ context()!index() ]

to something equivalent in XSLT. In MSXML docs, it says that context() is equivalent to context(-1). At topxml it says that current() in XSLT is equivalent to context(-1) in XSL. I know I can use > in place of $gt$ and position() in place of index(). However, there's no equivalent for the "bang operator" (!) and position() won't take an argument. So, I can't figure out how to get the position() of current().

Bind it to a variable, for example <xsl:variable name="current-position" select="position()"/> ... <xsl:value-of select="$foo[position() &gt; $current-position]"/>

J.Pietschmann


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