[xsl] How to get the Browser URL within XSL?

["Hubert Holtz" <Turnhose_alt@xxxxxxx>]

Hy all,

First of all I do not know if this is a pure xsl or cocoon question so i mail it to both lists.

I know I can access the request parameters of the url in xsl using the xsl-with-parameters type in my sitemap,
but how can I get the whole URL string in xsl.

The reason why I need to get this, is that I have the following URL structure:

http://www.somwhere.de/test/program.html?id=300&lang=ger

and I want to change the lang value to another value (eng i.e.) by clicking on my flag symbol, the problem is that I don't know
the sitename in front of .html, because I just want to change the lang parameter the rest should be the same,
depending on the last requested url (or is it possible to get this value inside xsl?) !

I'm using Cocoon 2.03 on tomcat4.1.

Any help is welcome.

Regards, Steve


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