Subject: RE: [xsl] selecting the nearest preceding sibling From: David Neary <David@xxxxxxxxx> Date: Tue, 13 May 2003 15:40:42 +0200 |
De : Mukul [mailto:mukulw3@xxxxxxxxx] > My XML file is below [snip] > I want to write **a XPATH expression which will select > the nearest preceding sibling , which contains a > particular element ( <a> in this example) ** . I do > not want preceding sibling which do not contain the > <a> tag (also the tag <a> should be nearest to the > context node) > > for e.g. if the context node is node 5 , the XPATH > expression which will select node 3(because it > contains element <a>) or for e.g. if the context node > is node 2 , the XPATH expression will select node > 1(because it contains element <a>) OK - the node set of all the preceding siblings which fit the criterium is given by preceding-sibling::tag[a] The nearest preceding sibling fitting the criterium is the last one in that nodeset (the nodes are always in document order)... that is, preceding-sibling::tag[a and last()] Hope this works, Cheers, Dave. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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