RE: [xsl] Modify XML and pass it to a template

Subject: RE: [xsl] Modify XML and pass it to a template
From: Jarno.Elovirta@xxxxxxxxx
Date: Wed, 14 May 2003 14:03:21 +0300

>   I would like to modify the XML input and then pass it to a 
> template. Is it possible? I want change a value and only 
> after made it, pass the xml to the template. I suppose that 
> my xsl will be like the following and in the part of ????? I 
> must insert the code to modify the content of variable 'contenuto'.
> [code xsl]
> <xsl:template match="/">
>      <xsl:variable name="contenuto">
> 	<xsl:copy-of select="."/>
>      </xsl:variable>
>     <xsl:variable name="contenutoModificato">
> 	?????
>      </xsl:variable>

Using a PI like e.g. <?contenuto?> to mark the position where to add the dynamic content would probably be a better solution. You can do this be first processing the stylesheet with XSLT, or write e.g. SAX filter to replace the PI. Should't be too difficult. However, are you sure you have to process the stylesheet? Unless you need to modify an XPath Expression, this might be doable by passing a parameter to the stylesheet and doing conditional processing in the RTF construction.


Jarno - Wumpscut: Totmacher (VNV Nation remix)

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