Subject: Fw: [xsl] Obtain XSL content From: Márcio Fernando Keller <marcio@xxxxxxxxxxxxx> Date: Wed, 14 May 2003 08:35:23 -0300 |
I would like, in some situations, to show a more friendly way to the user define the xsl content. Example: <xsl:choose> <xsl:when test="/Orders/SalesOrder/Customer/Gender='F'"> <xsl:text>Female</xsl:text> </xsl:when> <xsl:when test="/Orders/SalesOrder/Customer/Gender='M'"> <xsl:text>Male</xsl:text> </xsl:when> </xsl:choose> For the user, i would like to show: ------------------------- Source | Target ------------------------- F | Female M | Male | ------------------------- .... and permit to change this. Question: I think that i can use parser classes(ex xalan), xpath or process it like another xml file, but what the best method for this? Examples? Thanks | ----- Original Message ----- | From: "Michael Kay" <mhk@xxxxxxxxx> | To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> | Sent: Monday, May 12, 2003 10:03 PM | Subject: RE: [xsl] Obtain XSL content | | | | > | | > What is the best way to obtain the content of a xsl file. ... | | > | | > I need to know that exist a template for | | > "/Orders/SalesOrder/Customer/Gender" and tests with choose, | | | | You can read the stylesheet using document(''), as if it were another | | XML document. | | | | But it would be nice to know why you think you need to do this: what is | | the problem you are trying to solve? | | | | Michael Kay | | | | | | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list | | | | | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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Re: [xsl] Obtain XSL content, Márcio Fernando Kell | Thread | AW: [xsl] Apply-Templates, Elmar . Hurni |
RE: [xsl] Modify XML and pass it to, Jarno . Elovirta | Date | RE: [xsl] Using or ignoring Types i, Michael Kay |
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