Subject: Re: [xsl] Axis order and variables From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 23 May 2003 15:54:08 +0100 |
> I don't get it. I understood that a nodeset had an inherent ordering > which was established at the time we do the select on the nodeset... No if it had an inherent ordering it would be called a list or a sequence not a set. Note Xpath 2 does use sequences as primitive. Xpath 1 uses sets. "Node set" is not a tye in Xpath 2 drafts. <xsl:variable name="x" select="ancestor::x"/> <xsl:value-of select="$x[1]/@n"/> is equivalent to <xsl:value-of select="(ancestor::x)[1]/@n"/> the expression (ancestor::x) returns the set of all ancestors, the predicate 1 takes teh first element of that set in doc order, but note the ordering is a feature of teh [1] operation not of the result of the (ancestor::x) expression. > If we then select nodes from within that nodeset using > another axis, we go back to the document ordering associated with that > axis. > > Thanks for the clarification (hope I understand correctly now though). No. you are making it too complicated, there is no "going back" sets are unordered. Your intuition may have expected an ordering for <xsl:variable name="x" select="ancestor::x"/> but what would your intuition say for <xsl:variable name="x" select="ancestor::x|key('a','b')|child::z"/> <xsl:value-of select="$x[1]/@n"/> ? Fortunately you don't have to have to guess this as the answer is that select="ancestor::x|key('a','b')|child::z" returns an unordered set of all of the selected nodes. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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