RE: [xsl] position() seems always to be 1

[Jarno.Elovirta@xxxxxxxxx]

Hi,

> > Above, the position() returns the context position of the 
> > self:node() locations step, and will always return 1; last() 
> > will also always return 1 as the context size for self::* 
> > will never exceed 1. Thus, the above predicate test will 
> > always return true.
> 
> That makes sense, but then why does his test
> 
> > 	<xsl:when test="self::node()[position()=last()]">
> 
> always return false?  1 = 1, so you would expect the above to
> be true.  Yet Steve says that instead of the <xsl:when> clause,
> "it always uses the otherwise" clause.

I must have misread his question then, but the Expression above will always return true.

Cheers,

Jarno - Xorcist: I Just Want to Learn

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